

 %         One dimensional Newton code   
 %     User must provide an inline function for f and another
 %    for f',  called df.

  x = input('enter the starting value x0  ')
    format compact
   disp('  iterate       x            f(x)          est. error  ')
   for n =  0:5
      s = f(x)/df(x);
       sprintf('   %2d    %2.10f    %2.10f    % 2.10f \n', n,x,f(x),s)
       x = x-s;
     
   end
